Q :-
1. How many moles of methanol, CH3OH are there in 6.53x10^23 molecules of methanol?
2. How many formula units of sodium chloride are in 16.0 grams of sodium chloride?
3. How many atoms are in 145.6L of neon gas?
4. How many liters L of gas are there if there are 2.7x10^24 fluorine molecules?
5. There 3x10^24 atoms of hydrogen in a large container. How many molecules of hydrogen are there? How many liters of hydrogen gas?
A:-
1. divide the given number by Avogadro's number to get answer to first one.
2. In 16 grams, the number of formula units are: given wt/mol. wt = 16/58= 0.28 approx.
3. Good question. in 22.4 dm^3, it's one mole, for neon, so divide given volume by 22.4 dm^3 (1dm^3=1 L). Now multiply what you get by Avogadro's Number. This is number of atoms in the given sample.
4. This is pretty interesting. See:
First, divide given number by Avogadro's number then you'll get number of moles. Now for Fluorine, a diatomic element, we need to find what volume corresponds to one mole, so divide the value 22.4 by its valency 2, so its 11.2 litres, now the number of moles you got previously in this problem, go multiply this 11.2 with that number, you'll get the volume.
5. Here 3/2 x 10^24 molecules exist, as hydrogen normally exists in diatomic molecular form. Also, as in earlier problem divide the number of MOLECULES with Avogadro's number and then multiply the result by 11.2. You get the required volume of hydrogen in the container
1. How many moles of methanol, CH3OH are there in 6.53x10^23 molecules of methanol?
2. How many formula units of sodium chloride are in 16.0 grams of sodium chloride?
3. How many atoms are in 145.6L of neon gas?
4. How many liters L of gas are there if there are 2.7x10^24 fluorine molecules?
5. There 3x10^24 atoms of hydrogen in a large container. How many molecules of hydrogen are there? How many liters of hydrogen gas?
A:-
1. divide the given number by Avogadro's number to get answer to first one.
2. In 16 grams, the number of formula units are: given wt/mol. wt = 16/58= 0.28 approx.
3. Good question. in 22.4 dm^3, it's one mole, for neon, so divide given volume by 22.4 dm^3 (1dm^3=1 L). Now multiply what you get by Avogadro's Number. This is number of atoms in the given sample.
4. This is pretty interesting. See:
First, divide given number by Avogadro's number then you'll get number of moles. Now for Fluorine, a diatomic element, we need to find what volume corresponds to one mole, so divide the value 22.4 by its valency 2, so its 11.2 litres, now the number of moles you got previously in this problem, go multiply this 11.2 with that number, you'll get the volume.
5. Here 3/2 x 10^24 molecules exist, as hydrogen normally exists in diatomic molecular form. Also, as in earlier problem divide the number of MOLECULES with Avogadro's number and then multiply the result by 11.2. You get the required volume of hydrogen in the container
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